Integrand size = 22, antiderivative size = 113 \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=-\frac {3 d}{2 (b c-a d)^2 \sqrt {c+d x^2}}-\frac {1}{2 (b c-a d) \left (a+b x^2\right ) \sqrt {c+d x^2}}+\frac {3 \sqrt {b} d \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 (b c-a d)^{5/2}} \]
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Time = 0.06 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {455, 44, 53, 65, 214} \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=\frac {3 \sqrt {b} d \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 (b c-a d)^{5/2}}-\frac {3 d}{2 \sqrt {c+d x^2} (b c-a d)^2}-\frac {1}{2 \left (a+b x^2\right ) \sqrt {c+d x^2} (b c-a d)} \]
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Rule 44
Rule 53
Rule 65
Rule 214
Rule 455
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {1}{(a+b x)^2 (c+d x)^{3/2}} \, dx,x,x^2\right ) \\ & = -\frac {1}{2 (b c-a d) \left (a+b x^2\right ) \sqrt {c+d x^2}}-\frac {(3 d) \text {Subst}\left (\int \frac {1}{(a+b x) (c+d x)^{3/2}} \, dx,x,x^2\right )}{4 (b c-a d)} \\ & = -\frac {3 d}{2 (b c-a d)^2 \sqrt {c+d x^2}}-\frac {1}{2 (b c-a d) \left (a+b x^2\right ) \sqrt {c+d x^2}}-\frac {(3 b d) \text {Subst}\left (\int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx,x,x^2\right )}{4 (b c-a d)^2} \\ & = -\frac {3 d}{2 (b c-a d)^2 \sqrt {c+d x^2}}-\frac {1}{2 (b c-a d) \left (a+b x^2\right ) \sqrt {c+d x^2}}-\frac {(3 b) \text {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{2 (b c-a d)^2} \\ & = -\frac {3 d}{2 (b c-a d)^2 \sqrt {c+d x^2}}-\frac {1}{2 (b c-a d) \left (a+b x^2\right ) \sqrt {c+d x^2}}+\frac {3 \sqrt {b} d \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 (b c-a d)^{5/2}} \\ \end{align*}
Time = 0.33 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.90 \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=\frac {1}{2} \left (\frac {-2 a d-b \left (c+3 d x^2\right )}{(b c-a d)^2 \left (a+b x^2\right ) \sqrt {c+d x^2}}-\frac {3 \sqrt {b} d \arctan \left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {-b c+a d}}\right )}{(-b c+a d)^{5/2}}\right ) \]
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Time = 3.03 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.78
method | result | size |
pseudoelliptic | \(\frac {d \left (-\frac {b \sqrt {d \,x^{2}+c}}{2 \left (b \,x^{2}+a \right ) d}-\frac {3 \arctan \left (\frac {b \sqrt {d \,x^{2}+c}}{\sqrt {\left (a d -b c \right ) b}}\right ) b}{2 \sqrt {\left (a d -b c \right ) b}}-\frac {1}{\sqrt {d \,x^{2}+c}}\right )}{\left (a d -b c \right )^{2}}\) | \(88\) |
default | \(\text {Expression too large to display}\) | \(1203\) |
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Leaf count of result is larger than twice the leaf count of optimal. 226 vs. \(2 (93) = 186\).
Time = 0.31 (sec) , antiderivative size = 537, normalized size of antiderivative = 4.75 \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=\left [\frac {3 \, {\left (b d^{2} x^{4} + a c d + {\left (b c d + a d^{2}\right )} x^{2}\right )} \sqrt {\frac {b}{b c - a d}} \log \left (\frac {b^{2} d^{2} x^{4} + 8 \, b^{2} c^{2} - 8 \, a b c d + a^{2} d^{2} + 2 \, {\left (4 \, b^{2} c d - 3 \, a b d^{2}\right )} x^{2} + 4 \, {\left (2 \, b^{2} c^{2} - 3 \, a b c d + a^{2} d^{2} + {\left (b^{2} c d - a b d^{2}\right )} x^{2}\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b}{b c - a d}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right ) - 4 \, {\left (3 \, b d x^{2} + b c + 2 \, a d\right )} \sqrt {d x^{2} + c}}{8 \, {\left (a b^{2} c^{3} - 2 \, a^{2} b c^{2} d + a^{3} c d^{2} + {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x^{4} + {\left (b^{3} c^{3} - a b^{2} c^{2} d - a^{2} b c d^{2} + a^{3} d^{3}\right )} x^{2}\right )}}, -\frac {3 \, {\left (b d^{2} x^{4} + a c d + {\left (b c d + a d^{2}\right )} x^{2}\right )} \sqrt {-\frac {b}{b c - a d}} \arctan \left (\frac {{\left (b d x^{2} + 2 \, b c - a d\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b}{b c - a d}}}{2 \, {\left (b d x^{2} + b c\right )}}\right ) + 2 \, {\left (3 \, b d x^{2} + b c + 2 \, a d\right )} \sqrt {d x^{2} + c}}{4 \, {\left (a b^{2} c^{3} - 2 \, a^{2} b c^{2} d + a^{3} c d^{2} + {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x^{4} + {\left (b^{3} c^{3} - a b^{2} c^{2} d - a^{2} b c d^{2} + a^{3} d^{3}\right )} x^{2}\right )}}\right ] \]
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\[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=\int \frac {x}{\left (a + b x^{2}\right )^{2} \left (c + d x^{2}\right )^{\frac {3}{2}}}\, dx \]
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Exception generated. \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.29 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.35 \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=-\frac {3 \, b d \arctan \left (\frac {\sqrt {d x^{2} + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \sqrt {-b^{2} c + a b d}} - \frac {3 \, {\left (d x^{2} + c\right )} b d - 2 \, b c d + 2 \, a d^{2}}{2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} {\left ({\left (d x^{2} + c\right )}^{\frac {3}{2}} b - \sqrt {d x^{2} + c} b c + \sqrt {d x^{2} + c} a d\right )}} \]
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Time = 5.30 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.15 \[ \int \frac {x}{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}} \, dx=-\frac {\frac {d}{a\,d-b\,c}+\frac {3\,b\,d\,\left (d\,x^2+c\right )}{2\,{\left (a\,d-b\,c\right )}^2}}{b\,{\left (d\,x^2+c\right )}^{3/2}+\sqrt {d\,x^2+c}\,\left (a\,d-b\,c\right )}-\frac {3\,\sqrt {b}\,d\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {d\,x^2+c}\,\left (a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2\right )}{{\left (a\,d-b\,c\right )}^{5/2}}\right )}{2\,{\left (a\,d-b\,c\right )}^{5/2}} \]
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